Model Summary:
Granite-3.2-2B-Instruct is an 2-billion-parameter, long-context AI model fine-tuned for thinking capabilities. Built on top of
Granite-3.1-2B-Instruct
, it has been trained using a mix of permissively licensed open-source datasets and internally generated synthetic data designed for reasoning tasks. The model allows controllability of its thinking capability, ensuring it is applied only when required.
Supported Languages:
English, German, Spanish, French, Japanese, Portuguese, Arabic, Czech, Italian, Korean, Dutch, and Chinese. However, users may finetune this Granite model for languages beyond these 12 languages.
Intended Use:
This model is designed to handle general instruction-following tasks and can be integrated into AI assistants across various domains, including business applications.
Capabilities
Thinking
Summarization
Text classification
Text extraction
Question-answering
Retrieval Augmented Generation (RAG)
Code related tasks
Function-calling tasks
Multilingual dialog use cases
Long-context tasks including long document/meeting summarization, long document QA, etc.
Generation:
This is a simple example of how to use Granite-3.2-2B-Instruct model.
Then, copy the snippet from the section that is relevant for your use case.
from transformers import AutoModelForCausalLM, AutoTokenizer, set_seed
import torch
model_path="ibm-granite/granite-3.2-2b-instruct"
device="cuda"
model = AutoModelForCausalLM.from_pretrained(
model_path,
device_map=device,
torch_dtype=torch.bfloat16,
)
tokenizer = AutoTokenizer.from_pretrained(
model_path
)
conv = [{"role": "user", "content":"You have 10 liters of a 30% acid solution. How many liters of a 70% acid solution must be added to achieve a 50% acid mixture?"}]
input_ids = tokenizer.apply_chat_template(conv, return_tensors="pt", thinking=True, return_dict=True, add_generation_prompt=True).to(device)
set_seed(42)
output = model.generate(
**input_ids,
max_new_tokens=8192,
)
prediction = tokenizer.decode(output[0, input_ids["input_ids"].shape[1]:], skip_special_tokens=True)
print(prediction)
Example Outputs
thinking=True
Here is my thought process:
1. First, let's understand the composition of the initial 10 liters of 30% acid solution:
- Acid content = 30% of 10 liters = 0.30 * 10 = 3 liters
2. We want to end up with a 50% acid solution. Let's denote the volume of the 70% acid solution to be added as 'x' liters.
3. The amount of acid in the final mixture (50% solution) should equal the initial acid content plus the acid from the added 70% solution.
- Total acid in final mixture = 0.50 * (10 + x)
4. The equation representing the total acid content is:
3 (from initial solution) + 0.70 * x (from added solution) = 0.50 * (10 + x)
5. Now, we solve for 'x':
3 + 0.70x = 5 + 0.50x
0.70x - 0.50x = 5 - 3
0.20x = 2
x = 2 / 0.20
x = 10 liters
6. Therefore, 10 liters of a 70% acid solution must be added to the initial 10 liters of 30% acid solution to achieve a 50% acid mixture.
Here is my response:
To solve this problem, we need to determine how much of a 70% acid solution must be added to a 10-liter solution that is already 30% acid to create a new mixture that is 50% acid. Here's how to calculate it:
1.**Initial Acid Content**:
- The initial 10-liter solution contains 3 liters of acid (since 30% of 10 liters).
2.**Desired Final Acid Content**:
- We want the final mixture to be 50% acid.
3.**Equation Setup**:
- Let 'x' be the volume (in liters) of the 70% acid solution to be added.
- The equation representing the total acid content in the final mixture (which is 10 liters from the initial solution plus 'x' liters of the added solution) should equal 50% of the total volume (10 + x).
- This gives us: 3 (acid from initial solution) + 0.70x (acid from added solution) = 0.50(10 + x)
4.**Solving the Equation**:
- First, simplify the right side of the equation: 0.50(10 + x) = 5 + 0.50x
- Now, the equation is: 3 + 0.70x = 5 + 0.50x
- Subtract 0.50x from both sides: 0.20x = 2
- Divide both sides by 0.20: x = 2 / 0.20
- x = 10 liters
5.**Conclusion**:
- To achieve a 50% acid mixture from the initial 30% solution, you need to add 10 liters of a 70% acid solution.
So, the final answer is that 10 liters of a 70% acid solution must be added to the initial 10 liters of 30% acid solution.
thinking=False
To solve this problem, we'll use the concept of volume and concentration. Let's denote the amount of 70% acid solution we need to add as "x" liters.
First, let's find out how much acid is in the initial 10-liter solution:
Acid in initial solution = 30% of 10 liters = 0.30 * 10 = 3 liters
Now, we want to end up with a 50% acid solution in a total volume of (10 + x) liters. Let's denote the final volume as V.
Final acid concentration = 50%
Final acid amount = 50% of V = 0.50 * V
We know the initial acid amount and the final acid amount, so we can set up an equation:
Initial acid amount + Acid from added solution = Final acid amount
3 liters + (70% of x) = 0.50 * (10 + x)
Now, let's solve for x:
0.70x + 3 = 0.50 * 10 + 0.50x
0.70x - 0.50x = 0.50 * 10 - 3
0.20x = 5 - 3
0.20x = 2
x = 2 / 0.20
x = 10 liters
So, you need to add 10 liters of a 70% acid solution to the initial 10-liter 30% acid solution to achieve a 50% acid mixture.
Evaluation Results:
Models
ArenaHard
Alpaca-Eval-2
MMLU
PopQA
TruthfulQA
BigBenchHard
DROP
GSM8K
HumanEval
HumanEval+
IFEval
AttaQ
Llama-3.1-8B-Instruct
36.43
27.22
69.15
28.79
52.79
72.66
61.48
83.24
85.32
80.15
79.10
83.43
DeepSeek-R1-Distill-Llama-8B
17.17
21.85
45.80
13.25
47.43
65.71
44.46
72.18
67.54
62.91
66.50
42.87
Qwen-2.5-7B-Instruct
25.44
30.34
74.30
18.12
63.06
70.40
54.71
84.46
93.35
89.91
74.90
81.90
DeepSeek-R1-Distill-Qwen-7B
10.36
15.35
50.72
9.94
47.14
65.04
42.76
78.47
79.89
78.43
59.10
42.45
Granite-3.1-8B-Instruct
37.58
30.34
66.77
28.7
65.84
68.55
50.78
79.15
89.63
85.79
73.20
85.73
Granite-3.1-2B-Instruct
23.3
27.17
57.11
20.55
59.79
54.46
18.68
67.55
79.45
75.26
63.59
84.7
Granite-3.2-8B-Instruct
55.25
61.19
66.79
28.04
66.92
64.77
50.95
81.65
89.35
85.72
74.31
85.42
Granite-3.2-2B-Instruct
24.86
34.51
57.18
20.56
59.8
52.27
21.12
67.02
80.13
73.39
61.55
83.23
Training Data:
Overall, our training data is largely comprised of two key sources: (1) publicly available datasets with permissive license, (2) internal synthetically generated data targeted to enhance reasoning capabilites.
Infrastructure:
We train Granite-3.2-2B-Instruct using IBM's super computing cluster, Blue Vela, which is outfitted with NVIDIA H100 GPUs. This cluster provides a scalable and efficient infrastructure for training our models over thousands of GPUs.
Ethical Considerations and Limitations:
Granite-3.2-2B-Instruct builds upon Granite-3.1-2B-Instruct, leveraging both permissively licensed open-source and select proprietary data for enhanced performance. Since it inherits its foundation from the previous model, all ethical considerations and limitations applicable to
Granite-3.1-2B-Instruct
remain relevant.
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